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In Mathematics / High School | 2014-05-20

Determine if there is a possible solution for the system of equations:

1. \(x + 3y = 14\)
2. \(6x + 3y = -6\)

Asked by Kay721

Answer (2)

\left\{\begin{array}{ccc}x+3y=14\\6x+3y=-6&/\cdot(-1)\end{array}\right\\+\left\{\begin{array}{ccc}x+3y=14\\-6x-3y=6\end{array}\right\\-----------\\.\ \ \ \ \ -5x=20\ \ \ \ /:(-5)\\.\ \ \ \ \ \ \ \ \ \ x=-4\\\\-4+3y=14\\3y=14+4\\3y=18\ \ \ \ /:3\\y=6\\\\Solution:x=-4\ and\ y=6

Answered by Anonymous | 2024-06-10

The system of equations has a valid solution with x = − 4 and y = 6 . Both equations were satisfied after substituting the coordinates back into the originals. Thus, the two lines represented by these equations intersect at the point (-4, 6).
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Answered by Anonymous | 2024-12-24

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