How do you solve [tex]10^{-10\log 3}[/tex]?
Answer (2)
a l o g a b = b an d l o g a b c = c ⋅ l o g a b 1 0 − 10 l o g 3 = 1 0 l o g 3 − 10 = 3 − 10 3 − 10 = 3 10 1 = 59 049 1
The expression 1 0 − 10 l o g 3 simplifies to 3 − 10 , which is equal to 59 , 049 1 .
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