What volume of hydrogen is necessary to react with five liters of nitrogen to produce ammonia?
\[ \text{Reaction:} \quad N_2 + 3H_2 \rightarrow 2NH_3 \]
Answer (3)
Volume of hydrogen required to produce ammonia = 3 5 = 15L since, 1 mole of nitrogen reacts with 3 moles of hydrogen to produce ammonia. Amount of ammonia produced = 2 5 = 10L as 1 mole of nitrogen produces 2 moles of ammonia
To determine the volume of hydrogen required to react with five liters of nitrogen to produce ammonia, we refer to the balanced chemical equation:
N₂(g) + 3H₂(g) → 2NH₃(g)
This equation tells us that one volume of nitrogen gas reacts with three volumes of hydrogen gas. Therefore, if you have five liters of nitrogen, you would need three times that volume of hydrogen to react completely. Calculating this, we have:
5 liters N₂ x 3 liters H₂ per liter N₂ = 15 liters H₂
So, you would need 15 liters of hydrogen gas to react with 5 liters of nitrogen gas to produce ammonia, assuming constant pressure and temperature.
To react with five liters of nitrogen gas, 15 liters of hydrogen gas is necessary, based on the reaction equation N₂ + 3H₂ → 2NH₃. This is because one volume of nitrogen reacts with three volumes of hydrogen. Therefore, for five liters of nitrogen, you require 15 liters of hydrogen.
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