Solve for \(x\):
\[\tan x + \sqrt{3} = 0\]
Answer (2)
t an x + 3 = 0 t an x = − 3 ⟺ x = − 3 π + kπ ( k ∈ Z )
The solutions for tan x + 3 = 0 are x = 3 2 π + kπ and x = 3 5 π + kπ , where k is any integer. This indicates that there are infinitely many angles that satisfy the equation due to the periodicity of the tangent function. These solutions can be found in the second and fourth quadrants of the unit circle.
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