Find two consecutive numbers with a product of 121.

One number: x Its consecutive: x + 1
Product:
x(x+1)=121 x² + x - 121 = 0
Δ = 1² - 4.1.(-121) Δ = 1+484 Δ = 485
As square root of 485 is not integer, do not exist two consecutive numbers with product of 121

Answered by Ryan2 | 2024-06-10

There are no two consecutive numbers that multiply to give a product of 121. This conclusion is reached by setting up a quadratic equation and finding that the discriminant does not yield a perfect square. Therefore, no integer solutions exist for this problem.
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Answered by Ryan2 | 2025-06-15