To solve this problem, let's assign variables to represent the number of fiction books, non-fiction books, and picture books. Let F represent the number of fiction books, N represent the number of non-fiction books, and P represent the number of picture books.
We know that the total collection of books is 2630, so we can write the equation: F + N + P = 2630.
Next, we are given two pieces of information: the number of non-fiction books is 240 fewer than the number of fiction books, which can be represented as N = F - 240, and the number of non-fiction books is 190 more than the number of picture books, which can be represented as N = P + 190.
Now we can solve this system of equations to find the values of F, N, and P. Substitute the value of N in terms of F from the second equation into the first equation: F + (F - 240) + (P + 190) = 2630. Simplify the equation to get 2F + P - 50 = 2630. Rearrange the equation to isolate P: P = 2640 - 2F.
Since P represents the number of picture books, it must be a multiple of 12 (the number of books on each shelf). We can test different values of P that are multiples of 12 until we find a value that satisfies the equation. After solving the equation, we find that when P = 1320, F = 840 and N = 600.
Therefore, there are 840 fiction books, 600 non-fiction books, and 1320 picture books in the library.
The library contains 840 fiction books, 600 non-fiction books, and 1190 picture books. These values were found by setting up and solving a system of equations based on the book relationships given in the problem. Each book type's quantity was calculated step-by-step to ensure accuracy.
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