The volume of a regular hexagonal pyramid can be found using the formula V = (1/3) Bh, where B is the area of the base and h is the altitude. By substituting the values given in the question into the formula, we can find the volume to be 1500√3 cm³. ;
a lt i t u d e : H = 30 c m ba se p er im e t er = 60 c m P = 6 s 60 = 6 s / : 6 s = 10 c m
V o l u m e o f a re gu l a r h e x a g o na l p yr ami d i s g i v e n b y V = 2 3 ⋅ s 2 ⋅ h w h ere s i s t h e s i d e l e n g t h o f t h e h e x a g o n h i s i t s h e i g h t V = 2 3 ⋅ 1 0 2 ⋅ 30 = 3 ⋅ 100 ⋅ 15 = 1500 3 c m 3
The volume of the regular hexagonal pyramid with a base perimeter of 60 cm and an altitude of 30 cm is calculated to be 1500 3 c m 3 . This involves first determining the side length of the hexagon and its area, then applying the volume formula for pyramids. The final volume is therefore 1500 3 c m 3 .
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