Write an equation for the line parallel to \( y = -2x - 5 \) that contains the point \( P(-8, 4) \).

k : y = − 2 x − 5 an d l : y = m x + b k ∣∣ l ⇔ m = − 2 l : y = − 2 x + b P ( − 8 , 4 ) ∈ l ⇔ 4 = − 2 ⋅ ( − 8 ) + b ⇔ 4 = 16 + b ⇔ b = − 12 ⇒ l : y = − 2 x − 12

Answered by kate200468 | 2024-06-10

k : y = − 2 x − 5 l : y = m x + b k ∣∣ l ⟺ m = − 2 l : y = − 2 x + b ; P ( − 8 ; 4 ) − 2 ⋅ ( − 8 ) + b = 4 16 + b = 4 b = 4 − 16 b = − 12 A n s w er : y = − 2 x − 12

Answered by Anonymous | 2024-06-10

The equation of the line parallel to y = − 2 x − 5 that passes through the point P ( − 8 , 4 ) is y = − 2 x − 12 . This line has the same slope of -2 but a different y-intercept. Following point-slope form helps derive this equation accurately.
;

Answered by kate200468 | 2025-06-12