In rhombus ABCD, AB = 13 and AC = 25. Find the area of the rhombus to the nearest tenth.
Answer (2)
t h e a re a o f t h e r h o mb u s = = ha l f t h e p ro d u c t o f t h e d ia g o na l s o f a r h o mb u s A = 2 1 ⋅ ∣ A B ∣ ⋅ ∣ A C ∣ = 2 1 ⋅ 13 ⋅ 25 = 162.5 [ u 2 ]
The area of rhombus ABCD can be calculated using the lengths of its diagonals. With AB = 13 and AC = 25, we find the other diagonal using the Pythagorean theorem. The area is approximately 89.3 square units.
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