How many moles of \(\text{Ca(OH)}_2\) are in 25 mL of a 1.5 M solution?

Molar concentration is
C = V η ​
[ V ] = L i t ers
[ η ] = m o l
η = C ∗ V
V = 25 m L = 0.025 L
η = 1.5 ∗ 0.025
η = 0.0375 m o l es ​ ​

Answered by D3xt3R | 2024-06-10

There are 0.0375 moles of Ca(OH) 2 ​ in 25 mL of a 1.5 M solution. This is calculated using the formula for moles based on molarity and volume. Specifically, we used the values: C = 1.5 M and V = 0.025 L.
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Answered by D3xt3R | 2024-12-23