Given:
S = 100 m
t = 5 s
U = 0
Using the equation of motion:
s = ut + \frac{1}{2}at^2
Substitute the values:
100 = 0 \times 5 + \frac{1}{2} \times a \times (5)^2
Simplify:
100 = \frac{1}{2} \times a \times 25
Find acceleration (a).
Answer (2)
To find the acceleration using the given information, we will use the equation of motion:
s = u t + 2 1 a t 2
Here, the values are given as:
s = 100 meters (the displacement)
u = 0 meters per second (the initial velocity)
t = 5 seconds (the time)
Substituting these values into the equation:
100 = 0 × 5 + 2 1 × a × ( 5 ) 2
Simplifying the equation:
The term 0 × 5 is 0, so it can be removed.
The expression becomes: 100 = 2 1 × a × 25
To isolate a , the acceleration, we perform the following steps:
Multiply both sides by 2 to clear the fraction: 200 = a × 25
Divide both sides by 25 to solve for a : a = 25 200
Calculate the division: a = 8
Therefore, the acceleration a is 8 meters per second squared ( m/s 2 ).
This calculation shows how acceleration can be derived using the second equation of motion when the initial velocity is zero, displacement is known, and time is given.
The acceleration calculated from the given data is 8 meters per second squared (m/s²). This was determined using the equation of motion, where displacement, time, and initial velocity were substituted into the formula. The steps involved isolating the acceleration after simplifying the equation appropriately.
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