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In Mathematics / High School | 2025-07-03

How many times is the place value of 7 on the left greater than the place value of 7 on the right in the following numbers?

(i) 2,75,372
(ii) 87,28,729

Asked by Chuchee8372

Answer (1)

To solve the question of how many times the place value of 7 on the left is greater than the place value of 7 on the right, we will analyze each number given in the problem:

For the number 2,75,372:

The place value of the first 7 from the left is in the ten thousands place. Therefore, its place value is: Place value of 7 (left) = 7 × 10 , 000 = 70 , 000

The place value of the second 7 from the left is in the tens place. Therefore, its place value is: Place value of 7 (right) = 7 × 10 = 70

To find how many times the place value of the first 7 is greater than the place value of the second 7, we divide the place value of the first 7 by the place value of the second 7: 70 70 , 000 ​ = 1000


Therefore, the place value of the first 7 is 1000 times greater than the place value of the second 7 in 2,75,372.

For the number 87,28,729:

The place value of the first 7 from the left is in the ten-lakhs place. Therefore, its place value is: Place value of 7 (left) = 7 × 1 , 00 , 000 = 7 , 00 , 000

The place value of the second 7 from the left is in the hundreds place. Therefore, its place value is: Place value of 7 (right) = 7 × 100 = 700

To find how many times the place value of the first 7 is greater than the place value of the second 7, we divide the place value of the first 7 by the place value of the second 7: 700 7 , 00 , 000 ​ = 1000


Therefore, the place value of the first 7 is 1000 times greater than the place value of the second 7 in 87,28,729.


In both cases, the place value of the 7 on the left is 1000 times greater than the place value of the 7 on the right.

Answered by RyanHarmon181 | 2025-07-06

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