For what value of a does [tex]9=\left(\frac{1}{27}\right)^{a+3}[/tex]?

Question

lutfiproteam · Answer

9 = (1/27)^(a + 3) 
 3² = (3^(-3))^(a + 3) 
 3² = 3^(-3a - 9) 
 -3a - 9 = 2 
 -3a = 11 
 a = -11/3 
 Subject : Mathematics 
 Grade : 10 
 Chapter : Exponential Equations 
 #LutfiproTeam ;

For what value of a does [tex]9=\left(\frac{1}{27}\right)^{a+3}[/tex]?

Answer (1)

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