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In Mathematics / College | 2025-07-07

Is [tex]$W$[/tex] a subspace of [tex]$V$[/tex]? If not, state why. Assume that [tex]$V$[/tex] has the standard operations. (Select all that apply.)
[tex]$W=\left\{\left(x_1, x_2, x_3, 0\right): x_1, x_2,\text{ and } x_3 \text{ are real numbers }\right\}$[/tex]
[tex]$V=R^4$[/tex]

A. [tex]$W$[/tex] is a subspace of [tex]$V$[/tex].
B. [tex]$W$[/tex] is not a subspace of [tex]$V$[/tex] because it is not closed under addition.
C. [tex]$W$[/tex] is not a subspace of [tex]$V$[/tex] because it is not closed under scalar multiplication.

Asked by adrianajj

Answer (1)

The zero vector (0, 0, 0, 0) is in W.
W is closed under addition: if u, v are in W, then u + v is in W.
W is closed under scalar multiplication: if u is in W and c is a scalar, then cu is in W.
Therefore, W is a subspace of V. W is a subspace of V . ​

Explanation

Understanding the Problem We are given V = R 4 and W = {( x 1 ​ , x 2 ​ , x 3 ​ , 0 ) : x 1 ​ , x 2 ​ , x 3 ​ ∈ R } . We need to determine if W is a subspace of V . To do this, we need to check if W satisfies the following conditions:

The zero vector is in W .

W is closed under addition.

W is closed under scalar multiplication.

Checking the Conditions

Zero Vector: The zero vector in R 4 is ( 0 , 0 , 0 , 0 ) . Since W = {( x 1 ​ , x 2 ​ , x 3 ​ , 0 ) : x 1 ​ , x 2 ​ , x 3 ​ ∈ R } , we can see that ( 0 , 0 , 0 , 0 ) is in W because we can choose x 1 ​ = 0 , x 2 ​ = 0 , and x 3 ​ = 0 .

Closed under Addition: Let u = ( x 1 ​ , x 2 ​ , x 3 ​ , 0 ) and v = ( y 1 ​ , y 2 ​ , y 3 ​ , 0 ) be two vectors in W . Then their sum is u + v = ( x 1 ​ + y 1 ​ , x 2 ​ + y 2 ​ , x 3 ​ + y 3 ​ , 0 ) . Since x 1 ​ , x 2 ​ , x 3 ​ , y 1 ​ , y 2 ​ , y 3 ​ are real numbers, x 1 ​ + y 1 ​ , x 2 ​ + y 2 ​ , and x 3 ​ + y 3 ​ are also real numbers. Therefore, u + v is in W .

Closed under Scalar Multiplication: Let u = ( x 1 ​ , x 2 ​ , x 3 ​ , 0 ) be a vector in W and c be a scalar (a real number). Then c u = ( c x 1 ​ , c x 2 ​ , c x 3 ​ , 0 ) . Since x 1 ​ , x 2 ​ , x 3 ​ are real numbers and c is a real number, c x 1 ​ , c x 2 ​ , and c x 3 ​ are also real numbers. Therefore, c u is in W .

Conclusion Since W satisfies all three conditions, W is a subspace of V .


Examples
Understanding subspaces is crucial in fields like computer graphics, where transformations (e.g., rotations, scaling) are applied to objects represented as vectors. If these transformations maintain the object within a specific subspace, it simplifies computations and ensures certain properties are preserved. For instance, if an object is constrained to a 2D plane within a 3D space, transformations that keep it within that plane (a subspace) are more efficient to calculate and guarantee the object remains 2D.

Answered by GinnyAnswer | 2025-07-07