HRS - Ask. Learn. Share Knowledge. Logo

In Mathematics / High School | 2025-07-08

1. 6 + (9 - 3 x 4) 2. 3 x [(9 + 15) ÷ 8] 3. 4 x (18 - 2 x (16 - 8)) 4. (15 - 6) + (4 - 1) x 8 5. 2 x 3 (3 + 2 x (10 - 9))

Asked by AshantiLiz2509

Answer (1)

Let's solve each expression step-by-step using the order of operations: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right), often abbreviated as PEMDAS.

6 + (9 - 3 \times 4)

Start by solving the expression inside the parentheses: 9 − 3 × 4 = 9 − 12 = − 3 .
Now substitute back into the expression: 6 + ( − 3 ) = 6 − 3 = 3 .


3 \times [(9 + 15) \div 8]

First, solve inside the brackets: 9 + 15 = 24 .
Now divide: 24 ÷ 8 = 3 .
Finally, multiply: 3 × 3 = 9 .


4 \times (18 - 2 \times (16 - 8))

Start with the innermost parentheses: 16 − 8 = 8 .
Then multiply: 2 × 8 = 16 .
Substitute back: 18 − 16 = 2 .
Multiply by 4: 4 × 2 = 8 .


(15 - 6) + (4 - 1) \times 8

Compute inside the first set of parentheses: 15 − 6 = 9 .
Then compute inside the second set of parentheses: 4 − 1 = 3 .
Multiply the result by 8: 3 × 8 = 24 .
Finally, add: 9 + 24 = 33 .


2 \times 3 (3 + 2 \times (10 - 9))

Solve the innermost parentheses: 10 − 9 = 1 .
Then multiply: 2 × 1 = 2 .
Substitute back: 3 + 2 = 5 .
Multiply the whole expression: 2 × 3 × 5 = 6 × 5 = 30 .

Answered by SophiaElizab | 2025-07-21