Which code fragment can be used to meet the requirements? while (option != 0) { menu(); option = // code that reads the option goes here /* code that print the option go here */ } ○ do { menu(); option = // code that reads the option goes here /* code that print the option go here */ } while (option != 0); ○ while (option >= 0) { menu(); option = // code that reads the option goes here /* code that print the option go here */ } ○ for (option = 0; option != 0; option = //code that reads the option goes here) { /* code that print the option go here */ }

In this question, we are given different looping structure options in programming and asked to choose one that appropriately handles user input until a specified condition is met—specifically, until the user enters '0'.
Let's analyze the given options:

While Loop with Condition at the Beginning :
while (option != 0) { menu(); option = // code that reads the option goes here /* code that print the option goes here */ }
This loop checks the condition option != 0 before executing the block of code. This means if option initially equals 0, the loop will not execute at all. This is not ideal if we want the menu to be shown at least once before receiving a user's input.

Do-While Loop :
do { menu(); option = // code that reads the option goes here /* code that print the option goes here */ } while (option != 0);
The do-while loop executes the code block first and then checks the condition. Thus, the menu will be displayed at least once, making this loop suitable for scenarios where the user should see the menu before making a selection.

While Loop with a Different Condition :
while (option >= 0) { menu(); option = // code that reads the option goes here /* code that print the option goes here */ }
Here, the condition option >= 0 allows the loop to continue as long as the entered option is non-negative. However, this does not stop when option becomes 0, which may not meet the requirement if 0 is intended to exit the loop.

For Loop with Inappropriate Condition :
for (option = 0; option != 0; option = //code that reads the option goes here) { /* code that print the option goes here */ }
The for loop structure here initializes option to 0 and will not enter the loop body due to the option != 0 condition already failing. For this reason, this does not fulfill the task requirement.


Considering all these points, the most appropriate option is the Do-While Loop (Option 2). It allows the menu to be displayed once, and the user can input their choice, and it will continue looping until 0 is entered. This matches the typical use case where we show a menu and wait for user interaction repeatedly.

Answered by ElijahBenjaminCarter | 2025-07-20