Using the given digits only once, make all possible 3-digit numbers. Then arrange them in descending order: 6, 5, 9 8, 4, 1 2, 5, 3

Question

DanielJosephParker · Answer

To solve this question, we need to create all possible 3-digit numbers using the given digits and arrange them in descending order. The digits provided are: 6, 5, 9, 8, 4, 1, 2, 3. Note that each digit can only be used once per number. 
 Let's begin by selecting combinations of three different digits: 
 
 965 
 964 
 963 
 962 
 961 
 954 
 953 
 952 
 951 
 943 
 942 
 941 
 932 
 931 
 924 
 921 
 913 
 912 
 865 
 864 
 863 
 862 
 861 
 854 
 853 
 852 
 851 
 843 
 842 
 841 
 832 
 831 
 824 
 821 
 813 
 812 
 654 
 653 
 652 
 651 
 643 
 642 
 641 
 632 
 631 
 624 
 621 
 613 
 612 
 543 
 542 
 541 
 532 
 531 
 524 
 521 
 513 
 512 
 432 
 431 
 421 
 413 
 412 
 
 Finally, we arrange these numbers in descending order: 965, 964, 963, 962, 961, 954, ..., down to 412. 
 This process helps to systematically cover all possible 3-digit combinations without repeating any digit within the same number.

Using the given digits only once, make all possible 3-digit numbers. Then arrange them in descending order: 6, 5, 9 8, 4, 1 2, 5, 3

Answer (1)

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