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In Mathematics / High School | 2025-07-08

If 60% of a number is 120 more than 20% of the number, then 28% of the number is less than 33 1/3% of the number by? (a) 16 (b) 25 (c) 20 (d) 24

Asked by zackcarlson6807

Answer (1)

To solve this problem, we first need to translate the word problem into a mathematical equation. We can let the unknown number be x .

Formulate the Equation:


According to the problem, 60% of the number is 120 more than 20% of the number. This can be written as: 0.6 x = 0.2 x + 120


Solve for x :


Subtract 0.2 x from both sides: 0.6 x − 0.2 x = 120

Simplify the left side: 0.4 x = 120

Divide both sides by 0.4 to solve for x :
x = 0.4 120 ​ x = 300



Find 28% of the number and 33 1/3% of the number:


28% of x is 0.28 × 300 = 84 .

33 1/3% is the same as 3 1 ​ of the number. Hence, 3 1 ​ × 300 = 100 .



Determine how much 28% of the number is less than 33 1/3%:


Subtract the value of 28% of x from 33 1/3% of x :
100 − 84 = 16

Therefore, 28% of the number is 16 less than 33 1/3% of the number.
The correct answer is (a) 16.

Answered by EmmaGraceJohnson | 2025-07-22