Which of the following division sums will give the remainder zero and why?
(a) 47345 ÷ 5
(b) 53200 ÷ 100
(c) 325000 ÷ 1000
(d) 592005 ÷ 1000
Answer (2)
The division sums giving a remainder of zero are 47345 ÷ 5, 53200 ÷ 100, and 325000 ÷ 1000. Only 592005 ÷ 1000 does not result in a remainder of zero. Therefore, options (a), (b), and (c) are valid.
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To determine which of the division sums will give a remainder of zero, we need to check if each dividend is completely divisible by its divisor. A division problem has a remainder of zero when the dividend is an exact multiple of the divisor.
Let's evaluate each option:
47345 ÷ 5
To check divisibility by 5, the number must end in 0 or 5.
The number 47345 ends in 5, so it is divisible by 5.
Remainder: 0
53200 ÷ 100
A number is divisible by 100 if its last two digits are 00.
The number 53200 ends in 00, indicating divisibility by 100.
Remainder: 0
325000 ÷ 1000
A number is divisible by 1000 if its last three digits are 000.
The number 325000 ends in 000, meaning it’s divisible by 1000.
Remainder: 0
592005 ÷ 1000
A number is divisible by 1000 if its last three digits are 000.
The number 592005 ends in 005, which is not divisible by 1000.
Remainder: Not 0
From the evaluation, the division sums that will give a remainder of zero are options (a) 47345 ÷ 5 , (b) 53200 ÷ 100 , and (c) 325000 ÷ 1000 . Option (d) will not give a remainder of zero.
