What is the output of the following code?
```python
my_list = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']
i = 0
while i < len(my_list):
print(my_list[i])
i += 3
```
Choose the option that best answers the question.
A. adg
B. No output as the while loop does not execute
C. abcd
D. abcdefgh
Answer (2)
To determine the output of the given Python code, we need to evaluate the behavior of the while loop as it iterates over the list.
Here is a breakdown of the code execution:
my_list = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h'] i = 0 while i < len(my_list): print(my_list[i]) i += 3
Initialization : The variable i is initialized to 0, and we'll use this to index the list my_list.
While Loop Condition : The loop condition is i < len(my_list). Since the length of my_list is 8, the loop will continue as long as i is less than 8.
First Iteration :
i is 0, which is less than 8, so my_list[i] is 'a' and it is printed.
Then, i is incremented by 3, so i becomes 3.
Second Iteration :
i is 3, which is less than 8, so my_list[i] is 'd' and it is printed.
Again, i is incremented by 3, resulting in i being 6.
Third Iteration :
i is 6, which is less than 8, so my_list[i] is 'g' and it is printed.
i is incremented by 3, making i equal to 9.
End of Loop : Now i is 9, which is not less than 8, hence the loop exits.
Therefore, the output of the code is:
a d g
In multiple-choice terms, the correct answer is option 'adg' .
The output of the provided code is 'a', 'd', and 'g' printed on separate lines. This occurs because the while loop prints elements of the list at indices 0, 3, and 6. Therefore, the correct choice is option A: adg.
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