An electric device delivers a current of [tex]$15.0 A$[/tex] for 30 seconds. How many electrons flow through it?
Answer (2)
Translation preserves angle and side congruency.
Dilation preserves angle congruency but not side congruency (sides are proportional).
Corresponding angles are congruent after both translation and dilation.
Corresponding sides are congruent after the translation, but not after the dilation. C orres p o n d in g s i d es a reco n g r u e n t a f t er t h e t r an s l a t i o n , b u t n o t a f t er t h e d i l a t i o n .
Explanation
Analyze the transformations Let's analyze the transformations applied to triangle JKL. First, a translation is applied, and then a dilation. We need to determine how these transformations affect the congruence of corresponding angles and sides.
Effect of translation A translation shifts the triangle without changing its size or shape. Therefore, corresponding angles and corresponding sides remain congruent after the translation.
Effect of dilation A dilation changes the size of the triangle but preserves its shape. This means corresponding angles remain congruent after the dilation, but corresponding sides are no longer congruent; they are proportional.
Conclusion Based on the effects of translation and dilation, we can conclude that corresponding angles are congruent after both the translation and the dilation. However, corresponding sides are congruent after the translation but not after the dilation. Therefore, the correct statement is: Corresponding sides are congruent after the translation, but not after the dilation.
Examples
Imagine you're designing a logo. First, you shift the logo on the page (translation). The angles and side lengths of the logo remain the same. Then, you enlarge the logo (dilation). The angles remain the same, but the side lengths change proportionally, making the logo bigger but keeping its shape. This is how translations and dilations work in real-world applications.
A device delivering a current of 15.0 A for 30 seconds allows approximately 2.81 × 1 0 21 electrons to flow through it, calculated by finding the total charge and dividing by the charge of a single electron.
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