When asked to find the distance between the complex points $3+8 i$ and $7+6 i$, Zach showed the work below.
$=\sqrt{(3-7)^2+(8 i-6 i)^2}$
$=\sqrt{(-4)^2+(2 i)^2}$
$=\sqrt{16+4 i^2}$
$=\sqrt{16-4}$
$=\sqrt{12}$
$=2 \sqrt{3}$
He asked his friend Zöe to find his mistake, and she correctly told him that he should have:
A. subtracted the real and imaginary portions of the point in the same order.
B. left the $i$ out of the computations when finding distance in the complex plane.
C. remembered that -4 squared should be -16 , not 16 .
D. simplified $\sqrt{12}$ to $2 \sqrt{2}$ not in $2 \sqrt{2}$
Answer (3)
The minimum eccentricity would be zero.
A eccentricity of zero would be a circle, because if it's zero you only have one point ;
The minimum value of eccentricity is 0, which indicates a perfect circle. Values for eccentricity range from 0 (circle) to just below 1 (ellipse). Eccentricities of other shapes include 1 for parabolas and greater than 1 for hyperbolas.
;
