2x+3y=7 2(2)+3y=7 4+3y=7 subtract 4 from both sides 3y=3 divide both side by 3 y=1
2x+3y=7
2x+3=7
2x+3y=7
subtract 3y from both sides
2x=7-3y
divide both side by 2
x=3.5-1.5
x=2
then you do the x-y=1
x-y=1 2-1=1 1=1
in the end both answers are 1 so that means that i did it right. that means that x=2 and y=1
2x+3y=7 x-y=1
2x+3y=7 x=1+y
2*(1+y)+3y=7 x=1+y
2+2y+3y=7 x=1+y
5y=5 |(:5) x=1+y
y=1 x=2
CHECK: 2x+3y=7 x-y=1
2 2 + 3 1 = 7
x-y = 1 2-1 = 1
To solve the system of equations 2 x + 3 y = 7 and x − y = 1 , you can substitute x from the second equation into the first. This leads to y = 1 and consequently x = 2 . The final solution is x = 2 and y = 1 .
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