f(x) = a x^2 + b x + c; where a is not 0; f(-2) = -11 => 4a -2b + c = -11; f(4) = 13 => 16a +4b + c = 13; f(6) = 29 => 36a + 6b + c = 29; You must find a, b, c;
To find the quadratic function that passes through the points (-2, -11), (4, 13), and (6, 29), we set up a system of equations based on the general form of a quadratic equation. After solving the equations, we find the function is given by y = 2 1 x 2 + 3 x − 7 . This equation can be verified by plugging the x-values from the points into the equation to confirm they yield the corresponding y-values.
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