What is the molality of a solution in which 3.0 moles of NaCl are dissolved in 1.5 kg of water?

density H2O = 1g/cm³ 1,5 kg H2O = 1500g = 1500cm³ (1dm³ = 1000cm³)
3moles of NaCl-----in---------1500cm³ H2O x moles of NaCl ----in--------1000cm³ H2O x = 2moles of NaCl
answer: 2 mol/dm³

Answered by pyromorphite | 2024-06-10

The **molality **of the sodium chloride solution is 2.0 mol/kg.
Given:
**3.0 moles **of **NaCl **in **1.5 kilograms **of water .
To find:
The **molality **of the solution
Solution:
The moles of solute that is **sodium chloride **= 3.0 mol
The **mass of solvent **that is **water **= 1.5 kg
The **molality **of the solution :
= 1.5 k g 3.0 m o l ​ = 2.0 m o l / k g
The **molality **of the sodium chloride solution is 2.0 mol/kg.
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Answered by Tringa0 | 2024-06-24

The molality of the sodium chloride solution is 2.0 mol/kg, calculated from 3.0 moles of NaCl dissolved in 1.5 kg of water. Molality measures the concentration of a solution in terms of moles of solute per kilogram of solvent. In this case, the calculation is straightforward: 3.0 moles divided by 1.5 kg equals 2.0 mol/kg.
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Answered by Tringa0 | 2024-09-27