If a chemist analyzes a 3.84g sample containing sand and table sugar, and recovers 1.43g of sand, what percent by mass of table sugar should the chemist report for this sample?

3.84 - 1.43 = 2.41 2.41g of table sugar
% mass = ( (mass of element) / (total mass) ) * 100 % mass = (2.41 / 3.84) * 100 % mass = (0.6276) * 100 % mass = 62.76
62.76%

Answered by iloveonedirection | 2024-06-10

well you would use the formula, which is,
mass percent= g of solute/ g of solute+ of solvent
and then you multiply by 100.....so when I did it I did 1.43/3.84+1.43 and multiplied it by 100 giving me 27%

Answered by mathgeek | 2024-06-10

To calculate the percent by mass of table sugar in a 3.84 g sample containing 1.43 g of sand, we subtract the mass of sand from the total mass to get 2.41 g of table sugar. Then, using the formula for percent by mass, we find that the table sugar makes up approximately 62.76% of the sample. Therefore, the percent by mass of table sugar is 62.76%.
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Answered by iloveonedirection | 2024-09-04