A student investigated how the pressure in a diving pool varied with depth. He filled a balloon with helium and tied it to the end of a long pole. Then, he submerged the balloon to various depths and observed the result.
Which one of the following best describes what happened to the balloon as it went deeper?
(a) The balloon got larger because the pressure of the water around it increased compared with the pressure inside the balloon.
(b) The balloon got larger because the pressure of the water around it decreased compared with the pressure inside the balloon.
(c) The balloon got smaller because the pressure of the water around it increased compared with the pressure inside the balloon.
(d) The balloon got smaller because the pressure of the water around it decreased compared with the pressure inside the balloon.
Answer (3)
Pressure of water increases with depth. Thus, the balloon decreases in volume as it is forced deeper. The correct answer is C).
The balloon got smaller because the pressure of the water around it increased compared with the pressure inside the balloon. Therefore, the correct answer is (C).
As the student submerged the balloon to various depths, the pressure of the water around the balloon increased, which caused the balloon to get smaller. This is because the pressure inside the balloon remained constant, while the pressure outside increased.
The helium inside the balloon would have been compressed by the increased pressure of the water, causing the balloon to decrease in size. This phenomenon can be explained by Boyle's law, which states that the volume of a gas is inversely proportional to the pressure of its surroundings.
Learn more about Boyle's law , here:
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The balloon got smaller as it was submerged deeper because the pressure of the water increased, compressing the helium inside. This is consistent with Boyle's Law, where volume decreases as pressure increases. The correct answer is (c).
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