Given the balanced equation representing a reaction:
\[ \text{Al}_2(\text{SO}_4)_3 + 6\text{NaOH} \rightarrow 2\text{Al(OH)}_3 + 3\text{Na}_2\text{SO}_4 \]
The mole ratio of NaOH to Al(OH)3 is:
1. 1:1
2. 3:1
3. 1:3
4. 3:7
Answer (3)
The answer is number 2. 3:1. This is the simplified value of 6:2 which came from 6NaOH:2Al(OH)3. The original ratio is 6:2 but it can be simplified through dividing it each by 2. So 6 divided by 2 equals to 3 and 2 divided by 2 is 1. Therefore the simplified ratio is 3:1.
The mole ratio of NaOH to Al(OH)3 in the balanced chemical equation Al2(SO4)3 +6NaOH ==> 2Al(OH)3 + 3Na2SO4 can be determined by examining the coefficients of the compounds involved in the reaction.
For every 6 moles of NaOH, 2 moles of Al(OH)3 are produced. By dividing the moles of NaOH by the moles of Al(OH)3 (6/2), we see that the ratio simplifies to 3:1.
The mole ratio of NaOH to Al(OH)3 in the given balanced chemical equation is 3:1.
The mole ratio of NaOH to Al(OH)₃ from the balanced equation is 3:1. This is derived from the coefficients in the reaction which simplify from 6:2 to 3:1. Thus, the answer is option 2.
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