You would expect a phosphorus-chlorine bond to be:

1. Nonpolar, with neither end having a partial charge.
2. Polar, with neither end having a partial charge.
3. Nonpolar, with the chlorine end having a partial negative charge.
4. Polar, with the chlorine end having a partial negative charge.
5. Nonpolar, with the phosphorus end having a partial negative charge.
6. Polar, with the phosphorus end having a partial negative charge.

Explain why, please.

Answer: option 4. polar, with the chlorine end having a partial negative charge. ;

Answered by Edufirst | 2024-06-11

The correct answer is option 4: polar, with the chlorine end having a partial negative charge.
In a phosphorous -chlorine (P-Cl) bond, you would expect the bond to be polar, with the chlorine end having a **partial negative charge.
**When determining the polarity of a bond, we need to consider the electronegativity difference between the two atoms involved. Electronegativity is the ability of an atom to attract shared electrons in a chemical bond. The greater the electronegativity difference, the more polar the bond becomes.
In this case, chlorine (Cl) has a higher electronegativity value (3.16) compared to phosphorous (P) (2.19). This means that chlorine attracts the shared electrons in the bond more strongly than phosphorous does.
As a result, the electrons in the P-Cl bond are pulled closer to chlorine, creating a partial negative charge on the chlorine end. The phosphorous end, on the other hand, experiences a partial positive charge due to the electron density being reduced.
Therefore, the correct answer is option 4: polar, with the chlorine end having a partial negative charge.
To know more about chlorine:

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Answered by dhanashreevt1 | 2024-06-18

The correct answer is option 4: Polar, with the chlorine end having a partial negative charge. This occurs because chlorine has a higher electronegativity than phosphorus, causing an unequal sharing of electrons. As a result, chlorine attracts the electrons more strongly than phosphorus, leading to the partial charge distribution in the bond.
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Answered by Edufirst | 2024-10-09