A compound consists of 17.6% hydrogen and 82.4% nitrogen. Determine the empirical formula of the compound.

17,6% + 82,6% = 100%
mass of N = 14g mass of H = 1g
17,6% H = 17,6g H 82,4% N = 82,4g N
17,6g : 1g = 17,6 moles of H 82,4g : 14g = 5,89 moles of N
N : H = 5,89 : 17,6 ||:5,89 N : H = 1 : 2,99≈3
the empirical formula of the compound = NH₃ (ammonia)

Answered by pyromorphite | 2024-06-10

**Answer: The empirical formula for the given compound is ** N H 3 ​ ;

Answered by Alleei | 2024-06-12

The empirical formula of the compound with 17.6% hydrogen and 82.4% nitrogen is N H 3 ​ . This is determined by calculating the moles of each element and forming the simplest whole number ratio. Thus, the final empirical formula reflects the ratio of hydrogen to nitrogen as 3:1.
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Answered by Alleei | 2024-10-01