The density of aluminum is 2.70 g/cm\(^3\). A piece of aluminum foil that is 1000 cm on each side has a mass of 440 mg. How thick is the piece of foil?
Answer (2)
mass/volume = density mass = (440 mg)*(1g)/(1000mg) = 0.440g volume = (1000cm)(1000cm)(t) where t = thickness density = 2.70 g/cm^3 = (0.440g)/((1000cm)(1000cm)(t))
multiply both sides by 't' and divide both sides by (2.70g/cm^3)
t = (0.440) / ((1000cm)(1000cm)(2.70)) = 1.629x10^-7 cm
t = (1.629 x 10^-7 cm)*(1000000 micrometers)/(1 cm) = 0.1629 micrometers
Answer is t = 0.1629 micrometers
The thickness of the aluminum foil is calculated to be approximately 0.163 micrometers by using its mass and the density of aluminum. The mass was converted to grams, then used to find the volume, which was divided by the area of the foil. Finally, the thickness was converted into micrometers for a clearer understanding.
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