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Questions in mathematics

[Done] If [tex]f(x)=\left(x^m+9\right)^2[/tex], which statement about [tex]f(x)[/tex] is true? A. [tex]f(x)[/tex] is an even function for all values of [tex]m[/tex]. B. [tex]f(x)[/tex] is an even function for all even values of [tex]m[/tex]. C. [tex]f(x)[/tex] is an odd function for all values of [tex]m[/tex]. D. [tex]f(x)[/tex] is an odd function for all odd values of [tex]m[/tex].

[Done] Use [tex]f(x)=\frac{1}{2} x[/tex] and [tex]f^{-1}(x)=2 x[/tex] to solve the problems. [tex]\begin{array}{l} f(2)=\square \\ f^{-1}(1)=\square \\ f^{-1}(f(2))=\square \end{array}[/tex]

[Done] $6(3 x+1)-30=3(2 x-4)$

[Done] Write a verbal expression for the algebraic expression. [tex]6 z^2+4[/tex] A) six times [tex]z[/tex] times 2 increased by 4 B) six times [tex]z[/tex] squared increased by 4 C) six squared times [tex]z[/tex] plus 4 D) six more than 4 times [tex]z[/tex] squared

[Done] The position function of a particle is [tex]$s(t)=t^3-15 t$[/tex]. Find the velocity function [tex]$v(t)$[/tex] and the acceleration function [tex]$a(t)$[/tex] for the particle. [tex]$\begin{array}{l} v(t)=\square \ a(t)=\square\end{array}$[/tex]

[Done] What is 0.0540 in scientific notation?

[Done] Find the perimeter of a shape with sides of the following lengths: 1 3/7, 1 6/7, 1 3/7, 1 6/7

[Done] Solve the system of equations using your chosen method (Substitution, Elimination, or Graphing). [tex]\left\{\begin{array}{l} -3 x+3 y=3 \\ 5 x+3 y=-8 \end{array}\right.[/tex] Solution: ($\square$, $\square$)

[Done] Find the domain of [tex]f ( x )[/tex]. [tex]f(x)=\sqrt{7 x-49}[/tex]

[Done] The main cable of a suspension bridge is modeled by the equation [tex]y=0.0048(x-50)^2+6[/tex]. At what horizontal distances from the left support is the cable 10 ft above the roadway? [tex]y=[/tex] height in feet of cable above the roadway [tex]x=[/tex] horizontal distance in feet from left support Choose the equation one must solve to answer the question. [tex]0=0.0048(x-50)^2+6[/tex] [tex]10=0.0048(x-50)^2+6[/tex] [tex]y=0.0048(10-50)^2+6[/tex]