HRS - Ask. Learn. Share Knowledge. Logo

Questions in mathematics

[Done] The times it takes runners to complete a certain marathon are normally distributed with a mean of 4.6 hours and a standard deviation of 1.1 hours. What is the time for a runner with a [tex]$z$-score[/tex] of [tex]$-1.2$[/tex]? Enter your answer, rounded to the nearest hundredth, in the box.

[Done] $11+\frac{2}{9} b=23$

[Done] Consider the graph of some function $y=f(x)$. Evaluate $\lim _{x \rightarrow-4} f(x), \lim _{x \rightarrow 0} f(x)$, and $\lim _{x \rightarrow 6} f(x)$.

[Done] Which of the following is equivalent to $|x-1|<5$? A. $x-1<5$ B. $5 C. $-5 D. $-5>x-1<5$

[Done] To raise money for charity, Leo and his friends start the Pampered Pooch Pet Wash. The first day they are open, they forget to put up posters and only raise a little money. The next day, they hang posters all over the neighborhood and raise $56.75. In all, Leo and his friends raise $76.75 on the first two days they are open. Which equation can you use to find the amount of money Leo and his friends raise on the first day? A. [tex]$a+56.75=76.75$[/tex] B. [tex]$56.75 a=76.75$[/tex] C. [tex]$a-76.75=56.75$[/tex] D. [tex]$a-56.75=76.75$[/tex] Solve this equation for [tex]$a$[/tex] to find the amount of money Leo and his friends raise on the first day. $

[Done] Factor completely: 100-(x-y)^2

[Done] First, use the property for the power of a quotient. $\left(\frac{3}{4^5}\right)^2=\begin{array}{|l|} \hline ? \\ \frac{3^2}{4^2} \\ \frac{3^2}{4^5} \\ \frac{3^2}{\left(4^5\right)^2} \\ \frac{3}{\left(4^5\right)^2} \\ \hline \end{array}$

[Done] [\left[\left(\frac{1}{2}\right)^{10}\right]^{-3}

[Done] The hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh a total of 249 ounces. | Weight of Books | |---------------------------------------| | Number of Books | Weight per book (ounces) | Total Weight (ounces) | | Hard Cover | h | 7 | 7h | | Paperback | 45-h | 5 | x | | Total | 45 | | 249 | Which value could replace [tex]$x$[/tex] in the table? A. [tex]$40-h$[/tex] B. [tex]$50-h$[/tex] C. [tex]$5(45)-h$[/tex] D. [tex]$5(45-h)$[/tex]

[Done] \frac{2}{3}(6 c-18)+\frac{3}{4}(8 c+32)=-18