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Questions in mathematics
[Done] Create an equivalent system of equations using the system and the first equation. [tex] \begin{array}{l} x+4 y=8 \\ 4 x+y=2 \end{array} [/tex] [tex] \begin{array}{l} x+4 y=13 \\ 5 x+y=2 \end{array} [/tex] [tex]x+4 y=8[/tex] [tex]5 x+5 y=2[/tex] [tex] \begin{array}{l} x+4 y=8 \\ 4 x+5 y=10 \end{array} [/tex] [tex] \begin{array}{l} x+4 y=8 \\ 5 x+5 y=10 \end{array} [/tex]
[Done] $\begin{array}{l} \left(\begin{array}{llll} 1 & 3 & 8 & 5 \\ 5 & 4 & 6 & 2 \\ 6 & 7 & 1 & 8 \\ 2 & 9 & 3 & 7 \end{array}\right) \\ a _{ 4 1 }= \end{array}$
[Done] The point (-5, -9) was reflected over an axis to become the point (5, -9). Which axis was it reflected over? A. x-axis, because the x-coordinate is the opposite B. x-axis, because the y-coordinate is the opposite C. y-axis, because the x-coordinate is the opposite D. y-axis, because the y-coordinate is the opposite
[Done] Solve the following system of equations graphically: [tex] \begin{array}{c} y=-\frac{1}{3} x+3 \ 3 x-y=7 \end{array} [/tex]
[Done] Which of the following represents the area of a rectangle whose length is $x+1$ and whose width is $x+11$? A. $x^2+10 x+11$ B. $x^2+11 x+12$ C. $x^2+11$ D. $x^2+12 x+11$
[Done] $\Delta JKL$ has $j=7, k=11$, and $m \angle J=18^{\circ}$. Complete the statements to determine all possible measures of angle K. Triangle JKL meets the $\square$ criteria, which means it is the ambiguous case. Substitute the known values into the law of $\operatorname{sines}: \frac{\sin \left(18^{\circ}\right)}{7}=\frac{\sin (K)}{11}$. Cross multiply: $11 \sin \left(18^{\circ}\right)=$ $\square$ Solve for the measure of angle K, and use a calculator to determine the value. Round to the nearest degree: $m \angle K \approx$ $\square$ : However, because this is the ambiguous case, the measure of angle K could also be $\square$ .
[Done] Consider the equation: [tex]y=4 x-3[/tex] Which graph shows a line that is perpendicular to the line defined by the given equation? A. B.
[Done] Express as a product. [tex]$\log M^{20}$[/tex]
[Done] Find the least common denominator for these fractions. Enter your answer in the space provided. $\frac{2}{3}$ and $\frac{2}{7}$
[Done] $85,000 \times \frac{\left(\frac{0.05}{12}\right)}{\left(1+\frac{0.05}{12}\right)^{(12 \cdot 14)}-1}
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