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Questions in mathematics

[Done] What is the value of z in the sequence 1, 2, 4, 8, 10, 20, 22, z, ...? A. 44 B. 32 C. 24 D. 40

[Done] The average weight of 10 boys is 70 kg. But later, it was found that at two places the weight 54 kg was read as 44 kg and at one place weight 35 kg was read as 40 kg. Find the correct average weight (in kg).

[Done] Find the value of the following sequences: (i) 1 + 2 + 3 + 4 + 5 + ... + 29 + 30 + 29 + ... + 3 + 2 + 1 (ii) 1 + 2 + 3 + 4 + 5 + ... + 89 + 90 + 89 + ... + 3 + 2 + 1 (iii) 1 + 2 + 3 + 4 + 5 + ... + 44 + 45 + 44 + ... + 3 + 2 + 1

[Done] 7. Chairs are arranged in 27 rows and 27 columns in a party palace. How many chairs are there in the party palace altogether? b. In a class, each of the students contributed as many rupees as there are number of students. If total collection was Rs. 169, what was the number of students in the class?

[Done] Using the formula [tex]A=x(100-2 x)[/tex], complete the table of values given below. [tex] \begin{tabular}{|l|c|c|c|c|c|c|c|c|c|c|c|}\hline X & 0 & 5 & 10 & 15 & 20 & 25 & 30 & 35 & 40 & 45 & 50 \\ \hline (100-2 x) & 100 & & & & & & & & & & \\ \hline A=X(100-2 x) & 0 & & & & & & & & & & \\ \hline \end{tabular} [/tex]

[Done] Compute: [tex]$\frac{\left(1 \frac{1}{2}\right)^4}{\left(1 \frac{1}{2}\right)^2}$[/tex]

[Done] Dima called her friend to tell her that she saved $30 \%$ on her new skirt at a discount store. Her friend told her that she could have gotten a better deal at a different store that was advertising a sale of $\frac{1}{3}$ off all clothing. If the original price of Dima's skirt was $\$ 54$, how much more could she have saved at the store her friend suggested?

[Done] Solve for $y$. $\begin{array}{l} y+5=-2(x-1) \ y=[?] x+\square \end{array} $

[Done] To solve the equation $-x-3=x^2-2 x-15$, you could graph the following system: [tex]\begin{array}{l} y=-x-3 \ y=x^2-2 x-15\end{array}[/tex] Use the graph of this system to identify all solutions of $-x-3=x^2-2 x-15$. A. -7 B. -3 C. 0 D. 4

[Done] The expression $\sqrt[3]{2^5} \cdot \sqrt{2}$ is equivalent to